7 large watermelons were purchased for a party. Their weights were consecutive odd numbers, and averaged 37 lbs. What was the weight of the heaviest watermelon?
** There are two solutions **
Good luck Ed. :)
2 comments:
Anonymous
said...
The obvious answer is 43lbs. The existence of a second answer indicates that the question is poorly phrased. If you assume that "consecutive odd numbers" means a set of 7 odd integers such that n[i>0] = n[i-1]+2, and that you meant "mass" when you said "weight," and that all masses are given in pounds(mass), then there can be only one solution.
The obvious answer is 43lbs. The existence of a second answer indicates that the question is poorly phrased. If you assume that "consecutive odd numbers" means a set of 7 odd integers such that n[i>0] = n[i-1]+2, and that you meant "mass" when you said "weight," and that all masses are given in pounds(mass), then there can be only one solution.
2 comments:
The obvious answer is 43lbs. The existence of a second answer indicates that the question is poorly phrased. If you assume that "consecutive odd numbers" means a set of 7 odd integers such that n[i>0] = n[i-1]+2, and that you meant "mass" when you said "weight," and that all masses are given in pounds(mass), then there can be only one solution.
The obvious answer is 43lbs. The existence of a second answer indicates that the question is poorly phrased. If you assume that "consecutive odd numbers" means a set of 7 odd integers such that n[i>0] = n[i-1]+2, and that you meant "mass" when you said "weight," and that all masses are given in pounds(mass), then there can be only one solution.
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